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Etude sur les résidus de quelques fertilisants chimiques utilisés dans la riziculture au niveau de la vallée de l'Artibonite, Haà¯ti.


par Manouche DOUZE
Université de Liege  - Master de specialisation 2020
  

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ANNEXE 4 :

Annexe 4 : quelques photos lors de la réalisation de l'enquête

L'enquêteur (trice) parle avec les enquêtés

55

ANNEXE 5:

Annexe 5 : Presentation de l'analyse de variance entre le rendement et les doses des fertilisants appliquées

56

Analysis of Variance Table

Response: Azote

Df Sum Sq Mean Sq F value Pr(>F)

Anne 1 592352 592352 63.707 6.653e-15 ***

Residuals 643 5978677 9298

Signif. codes : 0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1

> LSD.test(MAzote,"Anne", group = T, main = "NULL", alpha = 0,01, console = T )

> library(agricolae)

> LSD.test(MAzote,"Anne", group = T, main = "NULL", alpha = 0,01, console = T )

Study: NULL

LSD t Test for Azote

Mean Square Error: 9298.098

Anne, means and individual

( 100

%)

CI

 
 

Azote

std

r

LCL

UCL

Min

Max

2017

176.9121

88.42193

134

-Inf

Inf

0

486.8691

2018

176.2827

141.70852

134

-Inf

Inf

0

1515.0705

2019

108.8902

75.12255

187

-Inf

Inf

0

367.8420

2020

107.5419

75.51957

190

-Inf

Inf

0

363.6169

Alpha: 0 ; DF Error: 643 Critical Value of t: Inf

Groups according to probability of means differences and alpha level( 0 ) Treatments with the same letter are not significantly different.

Azote groups

2017 176.9121 a

2018 176.2827 a

2019 108.8902 b

2020 107.5419 b

> duncan.test(MAzote,"Anne", group = T, main = "NULL", alpha = 0,01, console = T)

Study: NULL

Duncan's new multiple range test for Azote

Mean Square Error: 9298.098 Anne, means

 

Azote

std

r Min

Max

2017

176.9121

88.42193

134

0

486.8691

2018

176.2827

141.70852

134

0

1515.0705

2019

108.8902

75.12255

187

0

367.8420

2020

107.5419

75.51957

190

0

363.6169

Groups according to probability of means differences and alpha level( 0 ) Means with the same letter are not significantly different.

Azote groups

2017 176.9121 a

57

2018 176.2827 a

2019 108.8902 b

2020 107.5419 b

> Mphosphore = aov(Phosphore~ Anne, data = Manouchedata) > anova(Mphosphore)

Analysis of Variance Table

Response: Phosphore

Df Sum Sq Mean Sq F value Pr(>F)

Anne 1 1956 1955.8 0.6654 0.4149

Residuals 791 2325110 2939.5

> LSD.test(Mphosphore,"Anne", group = T, main = "NULL", alpha = 0,01, console = T)

Study: NULL

LSD t Test for Phosphore

Mean Square Error: 2939.457

Anne, means and individual ( 100 %) CI

Phosphore std r LCL UCL Min Max

2017 55.96056 55.94133 199 -Inf Inf 0 422.833

2018 55.99598 54.52703 199 -Inf Inf 0 422.833

2019 54.31937 54.64098 197 -Inf Inf 0 422.833

2020 51.83833 51.93137 198 -Inf Inf 0 422.833

Alpha: 0 ; DF Error: 791 Critical Value of t: Inf

Groups according to probability of means differences and alpha level( 0 ) Treatments with the same letter are not significantly different.

Phosphore groups

2018 55.99598 a

2017 55.96056 a

2019 54.31937 a

2020 51.83833 a

> MPotassium = aov(Potassium ~ Anne, data = Manouchedata) > anova(MPotassium )

Analysis of Variance Table

Response: Potassium

Df Sum Sq Mean Sq F value Pr(>F)

Anne 1 489 488.94 0.6654 0.4149

Residuals 791 581278 734.86

> LSD.test(MPotassium ,"Anne", group = T, main = "NULL", alpha = 0,01, consol e = T)

Study: NULL

LSD t Test for Potassium

Mean Square Error: 734.8642

Anne, means and individual ( 100 %) CI

Potassium std r LCL UCL Min Max

2017 27.98028 27.97066 199 -Inf Inf 0 211.4165

2018 27.99799 27.26351 199 -Inf Inf 0 211.4165

2019 27.15969 27.32049 197 -Inf Inf 0 211.4165

2020 25.91916 25.96569 198 -Inf Inf 0 211.4165

58

Alpha: 0 ; DF Error: 791 Critical Value of t: Inf

Groups according to probability of means differences and alpha level( 0 ) Treatments with the same letter are not significantly different.

Potassium groups

2018 27.99799 a

2017 27.98028 a

2019 27.15969 a

2020 25.91916 a

> duncan.test(MPotassium ,"Anne", group = T, main = "NULL", alpha = 0,01, con sole = T)

Study: NULL

Duncan's new multiple range test for Potassium

Mean Square Error: 734.8642 Anne, means

Potassium std r Min Max

2017 27.98028 27.97066 199 0 211.4165

2018 27.99799 27.26351 199 0 211.4165

2019 27.15969 27.32049 197 0 211.4165

2020 25.91916 25.96569 198 0 211.4165

Groups according to probability of means differences and alpha level( 0 ) Means with the same letter are not significantly different.

Potassium groups

2018 27.99799 a

2017 27.98028 a

2019 27.15969 a

2020 25.91916 a

> MRendement = aov(Rendement ~ Anne, data = Manouchedata) > anova(MRendement )

Analysis of Variance Table

Response: Rendement

Df Sum Sq Mean Sq F value Pr(>F)

Anne 1 1.8239e+08 182392880 0.3662 0.5453

Residuals 666 3.3172e+11 498082238

> LSD.test(MRendement ,"Anne", group = T, main = "NULL", alpha = 0,01, consol e = T)

Study: NULL

LSD t Test for Rendement

Mean Square Error: 498082238

Anne, means and individual ( 100 %) CI

Rendement std r LCL UCL Min Max

2017 6707.671 18274.11 167 -Inf Inf 0 162790.7

2018 7310.651 21128.62 167 -Inf Inf 0 198604.7

2019 7895.014 24297.29 167 -Inf Inf 0 224651.2

2020 8070.783 25051.08 167 -Inf Inf 0 249069.8

59

Alpha: 0 ; DF Error: 666 Critical Value of t: Inf

least Significant Difference: Inf

Treatments with the same letter are not significantly different.

Rendement groups

2020 8070.783 a

2019 7895.014 a

2018 7310.651 a

2017 6707.671 a

> duncan.test(MRendement ,"Anne", group = T, main = "NULL", alpha = 0,01, con sole = T)

Study: NULL

Duncan's new multiple range test for Rendement

Mean Square Error: 498082238 Anne, means

Rendement std r Min Max

2017

6707.671

18274.11

167

0

162790.7

2018

7310.651

21128.62

167

0

198604.7

2019

7895.014

24297.29

167

0

224651.2

2020

8070.783

25051.08

167

0

249069.8

Alpha: 0 ; DF Error: 666

Critical Range

2 3 4 Inf Inf Inf

Means with the same letter are not significantly different.

Rendement groups

2020 8070.783 a

2019 7895.014 a

2018 7310.651 a

2017 6707.671 a

> MRendement = aov(Rendement ~ Anne, data = Manouchedata) > anova(MRendement )

Analysis of Variance Table

Response: Rendement

Df Sum Sq Mean Sq F value Pr(>F)

Anne 1 1.8239e+08 182392880 0.3662 0.5453

Residuals 666 3.3172e+11 498082238 > shapiro.test(Rendement)

Shapiro-Wilk normality test

data: Rendement

W = 0.20617, p-value < 2.2e-16

> kruskal.test(Rendement ~ Anne, data = Manouchedata) Kruskal-Wallis rank sum test

data: Rendement by Anne

60

Kruskal-Wallis chi-squared = 4.4794, df = 3, p-value = 0.2141 > shapiro.test(Phosphore)

Shapiro-Wilk normality test

data: Phosphore

W = 0.70749, p-value < 2.2e-16

> shapiro.test(Potassium)

Shapiro-Wilk normality test

data: Potassium

W = 0.70749, p-value < 2.2e-16

> kruskal.test(Potassium ~ Anne, data = Manouchedata) Kruskal-Wallis rank sum test

data: Potassium by Anne

Kruskal-Wallis chi-squared = 0.77967, df = 3, p-value = 0.8543

> shapiro.test(Concentration) Shapiro-Wilk normality test

data: Concentration

W = 0.75369, p-value = 3.763e-08

> kruskal.test(Concentration ~ position, data = concentration) Kruskal-Wallis rank sum test

data: Concentration by position

Kruskal-Wallis chi-squared = 19.382, df = 2, p-value = 6.184e-05

> MConcentration = aov(Concentration ~ position, data = concentration) > anova(MConcentration)

Analysis of Variance Table

Response: Concentration

Df Sum Sq Mean Sq F value Pr(>F)

position 2 176.18 88.089 14.715 9.013e-06 ***

Residuals 51 305.30 5.986

---

Signif. codes: 0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1

> LSD.test(MConcentration ,"position", group = T, main = "NULL", alpha = 0,01

, console = T)

Study: NULL

LSD t Test for Concentration Mean Square Error: 5.986334

position, means and individual ( 100 %) CI

Concentration std r LCL UCL Min Max

am

10.00000 0.000000

9 -Inf Inf

10

10

av

15.83333 3.588703

12

-Inf Inf

10

20

ri

13.63636 2.261335

33

-Inf Inf

10

15

Alpha:

0 ; DF Error: 51

 
 
 
 

61

Critical Value of t: Inf

Groups according to probability of means differences and alpha level( 0 ) Treatments with the same letter are not significantly different.

Concentration groups

av 15.83333 a

ri 13.63636 ab

am 10.00000 b

> pairwise.wilcox.test(concentration$Concentration, concentration$position, p .adjust.method = "BH")

Pairwise comparisons using Wilcoxon rank sum test data: concentration$Concentration and concentration$position

am av

av 0.00076 -

ri 0.00036 0.03413

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